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Numbers n such that (n/4)^2-n/8=sum(k=1,n, k mod sum(i=0,k-1,1-t(i))) where t(i)=A010060(i) is the Thue-Morse sequence.
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%I #8 Jan 01 2024 13:20:14

%S 2,10,18,34,58,66,90,106,114,130,154,170,178,202,210,226,250,258,282,

%T 298,306,330,338,354,378,394,402,418,442,450,474,490,498,514,538,554,

%U 562,586,594,610,634,650,658,674,698,706,730,746,754,778,786,802,826

%N Numbers n such that (n/4)^2-n/8=sum(k=1,n, k mod sum(i=0,k-1,1-t(i))) where t(i)=A010060(i) is the Thue-Morse sequence.

%F It appears that for n>=1 a(n+2)=8*A000069(n)+2 (where A000069(n) are the odious numbers).

%K nonn

%O 1,1

%A _Benoit Cloitre_, May 27 2003