OFFSET
1,2
COMMENTS
Coefficients T_2(n,k) form the array A082171. These automata have no nontrivial automorphisms (by states).
Also equals the leftmost column of triangular matrix M=A103236, which satisfies: M^2 + 2*M = SHIFTUP(M) (i.e. each column of M shifts up 1 row). - Paul D. Hanna, Jan 29 2005
LINKS
Valery A. Liskovets, The number of connected initial automata, Kibernetika (Kiev), 3 (1969), 16-19 (in Russian; English translation: Cybernetics, 4 (1969), 259-262). [It includes the original methodology that he used in his 2003 and 2006 papers.]
Valery A. Liskovets, Exact enumeration of acyclic automata, Proc. 15th Conf. "Formal Power Series and Algebr. Combin. (FPSAC'03)", 2003.
Valery A. Liskovets, Exact enumeration of acyclic deterministic automata, Discrete Appl. Math., 154, No. 3 (2006), 537-551.
FORMULA
a(1) = 1 and a(n) := d_2(n-1)/(n-2)! for n >= 2, where d_2(n) := T_2(n, 1) - Sum_{j=1..n-1} binomial(n-1, j-1) * T_2(n-j, j+1) * d_2(j); and T_2(0, k) := 1, T_2(n, k) := Sum_{i=0..n-1} binomial(n, i) * (-1)^(n-i-1) *((i+k+1)^2 - 1)^(n-i) * T_2(i, k) for n > 0. [Edited by Petros Hadjicostas, Mar 06 2021 to agree with Theorem 3.3 (p. 543) in Liskovets (2006). Here, n + 1 is "the number of transient states including the pre-dead state".]
G.f.: 1 = Sum_{n>=0} a(n+1) * (x^n/(1-2*x)^n) * Product_{k=0..n} (1 - (3 + k)*x). Thus: 1 = 1*(1-3x) + 3*(x/(1-2x))*(1-3x)*(1-4x) + 15*(x^2/(1-2x)^2)*(1-3x)*(1-4x)*(1-5x) + 114*(x^3/(1-2x)^3)*(1-3x)*(1-4x)*(1-5x)*(1-6x) + ... - Paul D. Hanna, Jan 29 2005
MATHEMATICA
a[n_] := a[n] = If[n<1, 0, If[n == 1, 1, SeriesCoefficient[1-Sum[a[k+1]*x^k/(1-2*x)^k*Product[1-(j+3)*x, {j, 0, k}], {k, 0, n-2}], {x, 0,
n-1}]]]; Table[a[n], {n, 1, 15}] (* Jean-François Alcover, Dec 15 2014, after PARI *)
PROG
(PARI) {a(n)=if(n<1, 0, if(n==1, 1, polcoeff( 1-sum(k=0, n-2, a(k+1)*x^k/(1-2*x)^k*prod(j=0, k, 1-(j+3)*x+x*O(x^n))), n-1)))} \\ Paul D. Hanna, Jan 29 2005
/* Second PARI program using Valery A. Liskovets's recurrence: */
lista(nn)={my(T=matrix(nn+1, nn+1)); my(d=vector(nn)); my(a=vector(nn)); for(n=1, nn+1, for(k=1, nn, T[n, k] = if(n==1, 1, sum(i=0, n-2, binomial(n-1, i)*(-1)^(n-i-2)*((i + k + 1)^2 - 1)^(n-i-1)*T[i+1, k])))); for(n=1, nn, d[n] = T[n+1, 1] - sum(j=1, n-1, binomial(n-1, j-1)*T[n-j+1, j+1]*d[j])); for(n=1, nn, a[n] = if(n==1, 1, d[n-1]/(n-2)!)); a; } \\ Petros Hadjicostas, Mar 07 2021
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Valery A. Liskovets, Apr 09 2003
EXTENSIONS
More terms from Petros Hadjicostas, Mar 06 2021 using the above programs
STATUS
approved