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a(n) = 1^n + 7^n + 9^n.
0

%I #14 Jan 14 2018 18:27:37

%S 3,17,131,1073,8963,75857,649091,5606513,48811523,427774097,

%T 3769259651,33358386353,296270823683,2638754838737,23555015527811,

%U 210638693604593,1886253119421443,16909812213653777,151723048894909571

%N a(n) = 1^n + 7^n + 9^n.

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (17,-79,63).

%F From _Mohammad K. Azarian_, Dec 26 2008: (Start)

%F G.f.: 1/(1-x) + 1/(1-7*x) + 1/(1-9*x).

%F E.g.f.: e^x + e^(7*x) + e^(9*x). (End)

%F a(n) = 16*a(n-1) - 63*a(n-2) + 48 with a(0)=3, a(1)=17. - _Vincenzo Librandi_, Jul 21 2010

%t Table[1^n + 7^n + 9^n, {n, 0, 20}]

%Y Cf. A001550, A001576, A034513, A001579, A074501..A074580.

%K easy,nonn

%O 0,1

%A _Robert G. Wilson v_, Aug 23 2002