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A074488
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a(1)=1, then "jump over next cube": a(n) = 2*(a(n-1)+1)^3-a(n-1).
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0
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1, 15, 8177, 1093884103327, 2617845000308809034415180474721383777, 35880772304755070470965980424546414275930627947903988794595699467727630030276033995103117884255220637999070127
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OFFSET
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1,2
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COMMENTS
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The rule "jump over next something" can be varied, see A075694, A075695.
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LINKS
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FORMULA
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a(1)=1, a(n) = 2*(a(n-1)+1)^3-a(n-1).
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EXAMPLE
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a(1)=1; next cube is (a(1)+1)^3=8; "jump over" it: 8+(8-1)=15; a(2)=15; next cube is (a(2)+1)^3=4096; "jump over" it: 4096+(4096-15)=8177.
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MAPLE
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a(1) := 1; a(n) := 2*(a(n-1)+1)^2-a(n-1);
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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