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A073096 Maximal element in continued fraction for s(n) = sum( k>=n,1/2^(2^k) ). 0

%I #8 Mar 30 2012 18:39:05

%S 6,6,18,258,65538,4294967298,18446744073709551618,

%T 340282366920938463463374607431768211458,

%U 115792089237316195423570985008687907853269984665640564039457584007913129639938

%N Maximal element in continued fraction for s(n) = sum( k>=n,1/2^(2^k) ).

%F a(0)=6; for n>0 a(n)=2^(2^n)+2.

%F a(n) = A063486(n)-3 for n>0. - _R. J. Mathar_, Apr 22 2007

%e Continued fraction expansion of 1/2^(2^5)+1/2^(2^6)+1/2^(2^7)+...is [0, 4294967295, 4294967298, 4294967296, 4294967296,... ] where the maximum element is 4294967298, hence a(5)=4294967298

%Y Cf. A007400 for case n=0.

%K nonn

%O 0,1

%A _Benoit Cloitre_, Aug 18 2002

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