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%I #6 Mar 30 2012 18:39:03
%S 1,2,5,224,672,2737152,8895744,474439680,130660687872,
%T 4513732853760000,15798064988160000,894413525483520000,
%U 3194334019584000000,27610545531676262400000,8107146431738442547200000
%N a(n) = (2*n)!/core(n!)^2/(n+1) where core(x) is the squarefree part of x.
%o (PARI) for(n=1,50,print1((2*n)!/core(n!)^2/(n+1),","))
%K easy,nonn
%O 1,2
%A _Benoit Cloitre_, Jun 19 2002
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