OFFSET
1,1
COMMENTS
The next term in the series, a(9), is ~ 10^190.
The sequence gives the denominators for the fractional part of delta only. One could prefix four 1's in order to get (sum of reciprocals) = delta.
LINKS
Kevin Ryde, Table of n, a(n) for n = 1..10
FORMULA
a(n) = ceiling(1/(delta - 4 - Sum_{0 < i < n} 1/a(i))) is the smallest integer such that 4 + Sum_{i=1..n} 1/a(i) < delta = 4.6620... - M. F. Hasler, Apr 30 2018
PROG
(PARI) t=delta-4/*from A006890, or use: t=contfracpnqn(A069544); t[1, 1]/t[2, 1]*/; for(i=1, 8, print1(1\t+1", "); t-=1/(1\t+1)) \\ Requires delta to 93 decimals or A069544 to 90 terms (up to [..., 1, 1, 4]) to get a(7) correctly, 180 terms for a(8). - M. F. Hasler, Apr 30 2018
CROSSREFS
KEYWORD
frac,nonn
AUTHOR
Christopher Lund (clund(AT)san.rr.com), Apr 14 2002
EXTENSIONS
Edited by M. F. Hasler, Apr 30 2018
STATUS
approved