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Total number of holes in decimal expansion of the number n, assuming 4 has 1 hole.
9

%I #19 Feb 03 2017 02:33:09

%S 1,0,0,0,1,0,1,0,2,1,1,0,0,0,1,0,1,0,2,1,1,0,0,0,1,0,1,0,2,1,1,0,0,0,

%T 1,0,1,0,2,1,2,1,1,1,2,1,2,1,3,2,1,0,0,0,1,0,1,0,2,1,2,1,1,1,2,1,2,1,

%U 3,2,1,0,0,0,1,0,1,0,2,1,3,2,2,2,3,2,3,2,4,3,2,1,1,1,2,1,2,1,3,2,2,1,1,1,2

%N Total number of holes in decimal expansion of the number n, assuming 4 has 1 hole.

%H Indranil Ghosh, <a href="/A064692/b064692.txt">Table of n, a(n) for n = 0..50000</a>

%F a(A001742(n)) = 0. - _Michel Marcus_, Jul 25 2015

%e We assume decimal digits 1,2,3,5,7 have no hole; 0,4,6,9 have one hole each; 8 has two holes. So a(148)=3.

%t Table[DigitCount[x].{0, 0, 0, 1, 0, 1, 0, 2, 1, 1}, {x, 0, 104}] (* _Zak Seidov_, Jul 25 2015 *)

%o (Python)

%o def A064692(n):

%o ....x=str(n)

%o ....return x.count("0")+x.count("4")+x.count("6")+x.count("8")*2+x.count("9") # _Indranil Ghosh_, Feb 02 2017

%Y Cf. A001742, A064532, A064693, A206439, A064692, A208568.

%K base,easy,nonn

%O 0,9

%A _Matthew Conroy_, Oct 11 2001