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a(1) = 1; a(n+1) = smallest cube > a(n) with leading digit equal to final digit of a(n) and final digit not 0.
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%I #5 Dec 05 2013 19:54:50

%S 1,125,512,2197,74088,85184,405224,421875,531441,1030301,1061208,

%T 8120601,10077696,60236288,80062991,100544625,500566184,4004529472,

%U 20012875875,50039444125,50080192856,60006085875,500188017672

%N a(1) = 1; a(n+1) = smallest cube > a(n) with leading digit equal to final digit of a(n) and final digit not 0.

%H <a href="/index/Fi#final">Index entries for sequences related to final digits of numbers</a>

%e a(5) = 74088 = 42^3, hence a(6) = 85184 = 44^3.

%K nonn,base,easy

%O 1,2

%A _Amarnath Murthy_, May 03 2001

%E More terms from Larry Reeves (larryr(AT)acm.org), May 17 2001