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n^(n^n)-(n^n)^n with 0^0=1.
2

%I #14 Nov 05 2013 02:41:46

%S -1,0,0,7625597465304

%N n^(n^n)-(n^n)^n with 0^0=1.

%H Vincenzo Librandi, <a href="/A058124/b058124.txt">Table of n, a(n) for n = 0..5</a>

%F a(n) =A002488(n)-A002489(n)

%e a(2)=2^4-4^2=16-16=0. a(3)=3^27-27^3=7625597484987-19683=7625597465304

%Y Cf. A002488, A002489, A007925, A058125.

%K sign

%O 0,4

%A _Henry Bottomley_, Nov 10 2000

%E Offset corrected by _Arkadiusz Wesolowski_, Aug 24 2011