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A057194
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a(1) = 1; a(n+1) = (Product_{k=1..n} a(k)) * Sum_{k=1..n} a(k).
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4
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OFFSET
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1,3
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COMMENTS
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a(n) is about x^y^n with y = phi^2 = 2.61803398874... and x around 1.04200817421788490539. - Charles R Greathouse IV, Sep 12 2012
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LINKS
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FORMULA
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For n > 1; a(n+2) = a(n+1)^2 * ( a(n+1)/a(n) - a(n) + 1 ).
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EXAMPLE
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a(5) = (a(1)*a(2)*a(3)*a(4)) * (a(1)+a(2)+a(3)+a(4)) = 1*1*2*8 * (1+1+2+8) = 192.
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MATHEMATICA
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a[1] = 1; a[n_] := Product[a[i], {i, n - 1}] Sum[a[i], {i, n - 1}]; Array[a, 10] (* Robert G. Wilson v, Sep 03 2012 *)
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PROG
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(PARI)
v=vector(12, n, 1);
for (n=3, #v, v[n] = prod(k=1, n-1, v[k]) * sum(k=1, n-1, v[k] ) );
v057194=v
(Haskell)
a057194 n = a057194_list !! (n-1)
a057194_list = 1 : f 1 1 where
f u v = w : f (u * w) (v + w) where w = u * v
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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