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A054602
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Sum_{d|3} phi(d)*n^(3/d).
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10
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0, 3, 12, 33, 72, 135, 228, 357, 528, 747, 1020, 1353, 1752, 2223, 2772, 3405, 4128, 4947, 5868, 6897, 8040, 9303, 10692, 12213, 13872, 15675, 17628, 19737, 22008, 24447, 27060, 29853, 32832, 36003, 39372, 42945, 46728, 50727, 54948
(list; graph; refs; listen; history; internal format)
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OFFSET
| 0,2
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COMMENTS
| A054602=Product plus sum of 3 consecutive numbers. [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Oct 24 2009]
Contribution from Gary W. Adamson (qntmpkt(AT)yahoo.com), Jul 15 2010: (Start)
Continued fraction [n,n,n] = (n^2+1)/(n^3+2n) = (n^2+1)/a(n); e.g.
[7,7,7] = 50/357 (End)
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FORMULA
| a(n) =n^3+2n =A073133(n, 3). - Henry Bottomley (se16(AT)btinternet.com), Jul 16 2002
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MAPLE
| with(combinat, fibonacci):seq(fibonacci(4, i), i=0..38); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Dec 01 2006
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MATHEMATICA
| lst={}; Do[p=(n+2)*(n+1)*n+(n+2)+(n+1)+n; AppendTo[lst, p], {n, 0, 5!}]; lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Oct 24 2009]
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PROG
| (Other) sage: [lucas_number1(4, n, -1) for n in xrange(0, 39)] # [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), May 16 2009]
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CROSSREFS
| Sequence in context: A098500 A037236 A174963 * A083725 A192972 A159228
Adjacent sequences: A054599 A054600 A054601 * A054603 A054604 A054605
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KEYWORD
| nonn
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AUTHOR
| N. J. A. Sloane (njas(AT)research.att.com), Apr 16 2000
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