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Table of n, a(n) for n=0..42.
Index entries for sequences related to necklaces
a(2n) = a(n) + 2^(n-1), a(2n+1) = 2^n. - Ralf Stephan, Nov 01 2003
Sequence in context: A264393 A094858 A029940 * A276065 A143483 A264788
Adjacent sequences: A045671 A045672 A045673 * A045675 A045676 A045677
David W. Wilson