%I #10 Sep 14 2019 18:19:24
%S 0,0,0,0,0,0,24,28,128,252,720,1364,3360,6552,14616,29040,61440,
%T 122400,253008,504868,1028160,2054388,4149288,8294444,16679040,
%U 33349800,66895920,133775712,267976800,535920696,1072758840,2145452092
%N Number of 2n-bead balanced binary strings of fundamental period 2n, rotationally equivalent to complement, inequivalent to reverse and reversed complement.
%H Andrew Howroyd, <a href="/A045668/b045668.txt">Table of n, a(n) for n = 0..200</a>
%F It seems that a(n) = 4*n*A011948(n). - _Ralf Stephan_, Aug 30 2003
%F From _Andrew Howroyd_, Sep 14 2019: (Start)
%F a(n) = 2*n*A045686(n).
%F a(n) = A045663(n) - A045665(n). (End)
%Y Cf. A011948, A045663, A045665, A045686.
%K nonn
%O 0,7
%A _David W. Wilson_