OFFSET
1,1
MATHEMATICA
SequencePosition[Table[If[SequenceCount[IntegerDigits[n, 4], {0, 1}]>0 || SequenceCount[ IntegerDigits[ n, 4], {1, 0}]>0, 1, 0], {n, 600}], {1, 0}][[All, 1]] (* Requires Mathematica version 10 or later *) (* Harvey P. Dale, Sep 14 2016 *)
PROG
(Python)
from sympy.ntheory.factor_ import digits
def has01or10(k):
s = "".join(map(str, digits(k, 4)[1:])); return "01" in s or "10" in s
def ok(n): return has01or10(n) and not has01or10(n+1)
print(list(filter(ok, range(613)))) # Michael S. Branicky, Apr 20 2021
CROSSREFS
KEYWORD
nonn,base
AUTHOR
STATUS
approved