|
%I #19 Apr 26 2023 06:15:11
%S 362797056,4049565169664,584318301411328,17714700000000000,
%T 238572050223552512,1951354384207722496,11384956040305711104,
%U 52036560683837093888,197732674300000000000,650190514836423555072,1903193578437064103936,5062982072492057196544,12433743083946522728448
%N a(n) = (8*n+6)^11.
%H Vincenzo Librandi, <a href="/A017147/b017147.txt">Table of n, a(n) for n = 0..10000</a>
%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (12,-66,220,-495,792,-924,792,-495,220,-66,12,-1).
%F a(n) = 2048*A016847(n). - _R. J. Mathar_, Aug 26 2015
%F From _Amiram Eldar_, Apr 26 2023: (Start)
%F a(n) = A017137(n)^11.
%F Sum_{n>=0} 1/a(n) = 2047*zeta(11)/8388608 - 50521*Pi^11/60881161420800. (End)
%t (8*Range[0,20]+6)^11 (* _Harvey P. Dale_, Apr 30 2018 *)
%o (Magma) [(8*n+6)^11: n in [0..15]]; // _Vincenzo Librandi_, Jul 22 2011
%Y Cf. A013669, A016847, A017137.
%K nonn,easy
%O 0,1
%A _N. J. A. Sloane_
|
