A010202 Continued fraction for sqrt(149).

12, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1, 5, 3, 3, 5, 1, 4, 24, 4, 1

Offset

0,1

Links

Table of n, a(n) for n=0..83.

G. Xiao, Contfrac

Index entries for continued fractions for constants

Index entries for linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,0,1).

Mathematica

ContinuedFraction[Sqrt[149], 300] (* Vladimir Joseph Stephan Orlovsky, Mar 13 2011 *)
PadRight[{12}, 120, {24, 4, 1, 5, 3, 3, 5, 1, 4}] (* Harvey P. Dale, Apr 04 2020 *)

Prog

(Magma) SetDefaultRealField(RealField(120)); ContinuedFraction(Sqrt(149)); // Vincenzo Librandi, Apr 10 2020
(Python)
from sympy import sqrt
from sympy.ntheory.continued_fraction import continued_fraction_iterator
def aupton(nn):
    gen = continued_fraction_iterator(sqrt(149))
    return [next(gen) for i in range(nn+1)]
print(aupton(83)) # Michael S. Branicky, Dec 04 2021
(Python) # second version based on recurrence
def a(n): return 12 if n == 0 else [4, 1, 5, 3, 3, 5, 1, 4, 24][(n-1)%9]
print([a(n) for n in range(84)]) # Michael S. Branicky, Dec 04 2021

Crossrefs

Sequence in context: A038329 A098909 A261403 * A079792 A079791 A018812

Adjacent sequences: A010199 A010200 A010201 * A010203 A010204 A010205

Keyword

nonn,cofr

Author

N. J. A. Sloane

Status

approved