OFFSET
1,3
PROG
(Python)
from itertools import count
def b(n):
if n in [0, 2, 4, 8] or n % 10 == 0: return -1
for k in count(1):
if str(k) in str(k*n): return k
a, n, max = [], 0, -2
while len(a) < 10:
if (m := b(n)) > max:
a.append(n)
max = m
n += 1
print(a)
CROSSREFS
KEYWORD
nonn,new
AUTHOR
Dominic McCarty, Feb 26 2025
STATUS
approved