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A381136
a(n) is the number of divisors d of n such that tau(d^(1 + n) + n) = 2^omega(d^(1 + n) + n), where tau = A000005 and omega = A001221.
1
1, 2, 0, 1, 2, 4, 0, 0, 1, 3, 0, 2, 2, 3, 0, 1, 0, 2, 0, 2, 4, 2, 0, 1, 1, 2, 0, 2, 2, 8, 0, 1, 4, 4, 0, 1, 2, 3, 0, 2, 2, 7, 0, 1, 2, 4, 0, 1, 0, 2, 0, 2, 0, 2, 0, 2, 4, 2, 0, 3, 2, 2, 0, 1, 4, 8, 0, 2, 3, 5, 0, 1, 2, 3, 0, 2, 4, 8, 0, 1, 1, 3, 0, 4, 4, 4, 0
OFFSET
1,2
MATHEMATICA
Table[Length[Select[Divisors[n], DivisorSigma[0, #^(1+n)+n]==2^PrimeNu[#^(1+n)+n]&]], {n, 45}] (* James C. McMahon, Mar 05 2025 *)
PROG
(Magma) [#[d: d in Divisors(n) | #Divisors(d^(1+n)+n) eq 2^#PrimeDivisors(d^(1+n)+n)]: n in [1..50]];
(PARI) a(n) = sumdiv(n, d, my(f=factor(d^(1 + n) + n)); numdiv(f) == 2^omega(f)); \\ Michel Marcus, Feb 15 2025
CROSSREFS
KEYWORD
nonn,new
AUTHOR
EXTENSIONS
More terms from Jinyuan Wang, Mar 09 2025
STATUS
approved