A379595 Numbers k for which A376900(k) = k.

0, 385, 386, 387, 390, 392, 404, 405, 406

Offset

1,2

Comments

The primitive Pythagorean triples cause A376900(n) to grow slightly overproportionally in relation to n, apart from minor fluctuations. This is why this sequence is finite and full.

Links

Table of n, a(n) for n=1..9.

Felix Huber, Right Triangles belonging to A376900(k)=k

Maple

A379595:=proc(k)
   local a, p, q, v, m;
   a:=0;
   for p from 2 to evalf(sqrt(sqrt(2)*k+1)) do
      for q from 1 to min(p-1, floor(k/(sqrt(2)*p))) do
         if gcd(p, q)=1 and is(p+q, odd) then
            v:=max(p^2-q^2, 2*p*q);
            m:=min(p^2-q^2, 2*p*q)/v;
            a:=a+floor(k/v*sqrt(m^2-2*m+2));
         fi
      od
   od;
   if a=k then
      return k
   fi
end proc;
seq(A379595(k), k=0..1000);

Crossrefs

Cf. A376900.

Sequence in context: A254352 A274445 A227974 * A379983 A069043 A380995

Adjacent sequences: A379592 A379593 A379594 * A379596 A379597 A379598

Keyword

nonn,fini,full

Author

Felix Huber, Dec 26 2024

Status

approved