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Numbers k such that binomial(k^2,k) == 0 (mod k^3).
0

%I #16 Mar 26 2024 03:01:27

%S 1,2184,6552,12870,13860,19530,23100,33660,40755,47880,51051,58995,

%T 81396,88920,101010,113553,114114,114855,121800,125970,136136,141372,

%U 142290,142324,145860,150535,154583,157080,158928,164424,171080,180180,193732,195104,197340,214890,225680,229908,230230,230724,238602,243542,249964,253080,257712,267960,284867,291720,294525,297414,300696

%N Numbers k such that binomial(k^2,k) == 0 (mod k^3).

%o (PARI) isok(n) = binomial(n^2, n)%n^3==0;

%o (Python)

%o from itertools import count, islice

%o from math import comb

%o def A371474_gen(): # generator of terms

%o return filter(lambda k:not comb(k**2,k)%(k**3),count(1))

%o A371474_list = list(islice(A371474_gen(),3)) # _Chai Wah Wu_, Mar 25 2024

%Y Cf. A014062, A081370.

%K nonn

%O 1,2

%A _Seiichi Manyama_, Mar 24 2024

%E More terms from _Vaclav Kotesovec_, Mar 26 2024