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a(n) = Sum_{k=0..n} 2^(n-k) * k^n.
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%I #45 Dec 26 2023 05:15:33

%S 1,1,6,47,490,6417,101178,1866139,39425322,938856053,24883226698,

%T 726510389607,23169961642698,801435579830329,29884247978965146,

%U 1195036047465095027,51016725208899539626,2315820594694418639325,111384453953719146198762

%N a(n) = Sum_{k=0..n} 2^(n-k) * k^n.

%F a(n) ~ A309419 * n^n. - _Vaclav Kotesovec_, Dec 26 2023

%o (PARI) a(n) = sum(k=0, n, 2^(n-k)*k^n);

%Y Cf. A031971, A120485, A349963.

%K nonn,easy

%O 0,3

%A _Seiichi Manyama_, Dec 25 2023