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%I #11 Jan 19 2023 11:04:22
%S 1,-1,-1,1,0,0,0,0,0,-1,1,1,-1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,-1,1,1,
%T -1,0,0,0,0,0,1,-1,-1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
%U 0,-1,1,1,-1,0,0,0,0,0,1,-1,-1,1,0,0,0,0,0,0,0,0,0,0
%N Expansion of Product_{k>=0} (1 - x^(k^3+1)) in powers of x.
%H Seiichi Manyama, <a href="/A359942/b359942.txt">Table of n, a(n) for n = 0..10000</a>
%F a(0) = 1; a(n) = -(1/n) * Sum_{k=1..n} A359943(k) * a(n-k).
%o (PARI) a_vector(n) = my(v=vector(n+1)); v[1]=1; for(i=1, n, v[i+1]=-sum(j=1, i, sumdiv(j, d, ispower(d-1, 3)*d)*v[i-j+1])/i); v;
%Y Cf. A001093, A279484, A359936, A359943.
%K sign
%O 0
%A _Seiichi Manyama_, Jan 19 2023