%I #12 Jun 11 2022 13:51:12
%S 1,2,3,4,5,6,7,8,9,31381059609,1853020188851841
%N Numbers k such that k equals {alternating sum of digits of k} raised to the power of {number of digits of k}.
%C These are the only terms of this sequence.
%e 31381059609 = (9-0+6-9+5-0+1-8+3-1+3)^11.
%o (Python)
%o def A(n):
%o counter = 0
%o S = 0
%o q = n
%o while q:
%o q, c = q//10, q % 10
%o S += (-1)** counter * c
%o counter += 1
%o return S ** counter
%o def fixed_points_of_A():
%o for i in range(1,100):
%o m = int(10 ** (1 - 1/ i)) +1
%o for k in range(m, 10):
%o n = k**i
%o e = A(n)
%o if n ==e: print(n, k, i) #prints n, the value of the alternating sum, and of the power to which is raised this number.
%Y Fixed points of A353906.
%Y Cf. A055017 (alternating sum starting from the last digit of n).
%Y Cf. A055642 (number of digits of n).
%K nonn,easy,base,fini,full
%O 1,2
%A _Malo David_, May 10 2022