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a(n) = A349613(n) + A349614(n).
3

%I #8 Nov 25 2021 20:29:06

%S 2,0,0,0,0,0,0,0,1,0,0,-6,0,0,14,9,0,-14,0,-42,4,0,0,54,49,0,-17,-12,

%T 0,-118,0,-36,10,0,28,124,0,0,28,144,0,-24,0,-30,-215,0,0,-167,4,-140,

%U 34,-84,0,187,70,12,30,0,0,626,0,0,-114,69,196,-106,0,-102,26,-12,0,-508,0,0,-785,-90,20,-254,0,-287,125

%N a(n) = A349613(n) + A349614(n).

%H Antti Karttunen, <a href="/A349615/b349615.txt">Table of n, a(n) for n = 1..20000</a>

%H <a href="/index/Ed#EKG">Index entries for sequences related to EKG sequence</a>

%F a(1) = 2, and for n > 1, a(n) = -Sum_{d|n, 1<d<n} A349613(d) * A349614(n/d). [As the sequences are Dirichlet inverses of each other]

%o (PARI) A349615(n) = (A349613(n)+A349614(n)); \\ Needs also code from A349613 and A349614.

%Y Cf. A349613, A349614.

%K sign

%O 1,1

%A _Antti Karttunen_, Nov 23 2021