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A349525 a(n) = Sum_{k=0..n} (3*k+1)^(k-1) * Stirling2(n,k). 9

%I #37 Jul 29 2022 08:43:35

%S 1,1,8,122,2847,90112,3611162,175352515,10009442658,656934750150,

%T 48744407335597,4035143806865514,368706775967717518,

%U 36861117438297883213,4002400525694764367212,469049713401827161071110,59010099414303871987517111,7932542361585921797125908876

%N a(n) = Sum_{k=0..n} (3*k+1)^(k-1) * Stirling2(n,k).

%H Seiichi Manyama, <a href="/A349525/b349525.txt">Table of n, a(n) for n = 0..331</a>

%F E.g.f.: (-LambertW(3*(-exp(x) + 1)) / (3*(exp(x) - 1)))^(1/3).

%F E.g.f.: exp(-LambertW(3 - 3*exp(x))/3).

%F a(n) ~ c * d^n * n! / n^(3/2), where d = 1/log(1 + 1/(3*exp(1))) and c = exp(1/3) * sqrt((1 + 3*exp(1)) * log(1 + 1/(3*exp(1))) / (2*Pi))/3 = 0.190981550465823640438134269765128596177617920807463710992027181154754728...

%F a(n) ~ sqrt(1 + 3*exp(1)) * n^(n-1) / (3*exp(n - 1/3) * log(1 + 1/(3*exp(1)))^(n - 1/2)).

%F E.g.f. satisfies: log(A(x)) = (exp(x) - 1) * A(x)^3.

%F G.f.: Sum_{k>=0} (3*k+1)^(k-1) * x^k/Product_{j=1..k} (1 - j*x). - _Seiichi Manyama_, Nov 20 2021

%p b:= proc(n, m) option remember; `if`(n=0,

%p (3*m+1)^(m-1), m*b(n-1, m)+b(n-1, m+1))

%p end:

%p a:= n-> b(n, 0):

%p seq(a(n), n=0..24); # _Alois P. Heinz_, Jul 29 2022

%t Table[Sum[(3*k+1)^(k-1)*StirlingS2[n, k], {k, 0, n}], {n, 0, 20}]

%t nmax = 20; CoefficientList[Series[(-LambertW[3*(-E^x + 1)]/(3*(E^x - 1)))^(1/3), {x, 0, nmax}], x] * Range[0, nmax]!

%o (PARI) a(n) = sum(k=0, n, (3*k+1)^(k-1)*stirling(n, k, 2)); \\ _Seiichi Manyama_, Nov 20 2021

%o (PARI) N=20; x='x+O('x^N); Vec(sum(k=0, N, (3*k+1)^(k-1)*x^k/prod(j=1, k, 1-j*x))) \\ _Seiichi Manyama_, Nov 20 2021

%Y Cf. A000110, A008277, A052880, A349505, A349524.

%K nonn

%O 0,3

%A _Vaclav Kotesovec_, Nov 20 2021

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Last modified April 23 15:20 EDT 2024. Contains 371916 sequences. (Running on oeis4.)