%I #12 Jan 15 2025 06:49:09
%S 1,1,1,2,1,2,3,1,1,3,12,3,2,3,12,10,2,1,1,2,10,60,10,4,3,4,10,60,105,
%T 15,5,3,3,5,15,105,280,35,10,5,4,5,10,35,280,252,28,7,3,2,2,3,7,28,
%U 252,2520,252,56,21,12,10,12,21,56,252,2520
%N Triangle read by rows, T(n, k) = (lcm_{k=0..n} binomial(n, k)) / binomial(n, k).
%e Triangle starts:
%e [0] 1;
%e [1] 1, 1;
%e [2] 2, 1, 2;
%e [3] 3, 1, 1, 3;
%e [4] 12, 3, 2, 3, 12;
%e [5] 10, 2, 1, 1, 2, 10;
%e [6] 60, 10, 4, 3, 4, 10, 60;
%e [7] 105, 15, 5, 3, 3, 5, 15, 105;
%e [8] 280, 35, 10, 5, 4, 5, 10, 35, 280;
%e [9] 252, 28, 7, 3, 2, 2, 3, 7, 28, 252;
%p b := n -> ilcm(seq(binomial(n, k), k=0..n)):
%p A349203 := (n, k) -> b(n)/binomial(n, k):
%p seq(seq(A349203(n, k), k = 0..n), n = 0..11);
%Y Cf. A007318, A347563, A025533 (row sums), A002944 (column 0 and main diagonal).
%K nonn,tabl
%O 0,4
%A _Peter Luschny_, Nov 13 2021