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 A340114 Table T(n,k), n>=1, k>=1, row n being the lexicographically earliest of the longest sequences of distinct positive integers in which the k-th term does not exceed n*k and the smaller of adjacent terms divides the larger, giving a prime. 2
 1, 2, 1, 3, 6, 2, 4, 8, 1, 2, 4, 12, 6, 18, 9, 3, 15, 30, 10, 5, 35, 7, 21, 42, 14, 28, 56, 8, 16, 48, 24, 72, 36, 2, 1, 3, 9, 18, 6, 12, 24, 8, 40, 20, 10, 5, 55, 11, 33, 66, 22, 44, 4, 52, 26, 78, 39, 13, 91, 7, 49, 98, 14, 42, 126, 63, 21, 105, 15, 45, 135, 27, 81 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS The longest sequence is finite for all n. We can deduce this, because we know from the work of Saias that A337125(m)/m * log m is bounded, where A337125(m) is the length of the longest simple path in the divisor graph of {1,...,m}. See the comment in A337125 giving constraints on its terms. The sequence of row lengths starts 2, 6, 25, 97. LINKS Peter Munn, Rows n = 1..4 of triangle, flattened E. Saias, Applications des entiers à diviseurs denses, Acta Arithmetica, 83, 3 (1998), 225-240. FORMULA For n >= 1, 1 <= k <= row length(n), T(n,k) <= n * k. For n >= 1, 1 <= k < row length(n), max(T(n,k+1)/T(n,k), T(n,k)/T(n,k+1)) is in A000040. EXAMPLE For n = 1, the only sequences of distinct positive integers that have their k-th term not exceeding 1*k = k, are those whose n-th term is k. The longest such sequence in which the smaller of adjacent terms divides the larger, giving a prime, is (1, 2), since 3/2 is 1.5. So row 1 has length 2, with T(1,1) = 1, T(1,2) = 2. Table begins: 1, 2; 1, 3, 6, 2, 4, 8; 1, 2, 4, 12, 6, 18, 9, 3, 15, 30, 10, 5, 35, 7, 21, 42, 14, 28, 56, 8, 16, 48, 24, 72, 36; ... CROSSREFS Cf. A000040, A300012, A337125, A339491. Sequence in context: A292222 A182928 A141476 * A212360 A145888 A213935 Adjacent sequences:  A340111 A340112 A340113 * A340115 A340116 A340117 KEYWORD nonn,hard,tabf AUTHOR Peter Munn, Dec 28 2020 STATUS approved

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Last modified June 21 09:08 EDT 2021. Contains 345358 sequences. (Running on oeis4.)