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%I #18 Mar 20 2020 14:28:12
%S 1,3,5,3585,4911,5709,1688565,7361691,16747709
%N Positive integers n such that 17^n == 2 (mod n).
%o (PARI) for(k=1, 1e6, if(Mod(17, k)^k==2, print1(k", ")))
%o (Python)
%o A333269_list = [n for n in range(1,10**6) if n == 1 or pow(17,n,n) == 2] # _Chai Wah Wu_, Mar 14 2020
%Y Cf. Solutions to b^n == 2 (mod n): A015919 (b=2), A276671 (b=3), A130421 (b=4), A124246 (b=5), A277401 (b=7), A116622 (b=13), this sequence (b=17).
%K nonn,more
%O 1,2
%A _Seiichi Manyama_, Mar 14 2020
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