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%I #46 Mar 20 2020 12:58:14
%S 1,3,413,1329,6587,11629,75761,925071199
%N Positive integers k such that 11^k == 2 (mod k).
%C Next term > 10^10.
%o (PARI) for(k=1, 1e6, if(Mod(11, k)^k==2, print1(k", ")))
%Y Solutions to b^n == 2 (mod n): A015919 (b=2), A276671 (b=3), A130421 (b=4), A124246 (b=5), A277401 (b=7), this sequence (b=11), A116622 (b=13), A333269 (b=17).
%Y Cf. A015960.
%K nonn,more
%O 1,2
%A _Seiichi Manyama_, Mar 20 2020
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