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A332097 Maximum of s^n - Sum_{0 < x < s} x^n. 6

%I #16 May 25 2020 19:10:39

%S 1,1,4,28,317,4606,84477,1919575,47891482,1512466345,48627032377,

%T 1930020260416,77986967769593,3624337209819538,178110510699972510,

%U 9381158756438306167,548676565488760277878,31900481466759651567625,2189463436999785648552851,144075114432622269076465962

%N Maximum of s^n - Sum_{0 < x < s} x^n.

%C For small values of s, we have Sum_{0 < x < s} x^n ~ (s-1)^n, but for s > n/log(2) + 1.5 (cf. A332101) the difference E(s) = s^n - Sum_{0 < x < s} x^n becomes negative. Just before, the difference has its maximum: We have E(s) < E(s+1) <=> 2*s^n < (s+1)^n <=> s < 1/(2^(1/n)-1), so E takes its maximum at s = A078607(n), the least integer larger than this limiting value. This appears to be almost always equal to A332101(n) - 2.

%H Alois P. Heinz, <a href="/A332097/b332097.txt">Table of n, a(n) for n = 0..367</a>

%F a(n) = s^n - Sum_{0 < x < s} x^n for s = ceiling(1/(2^(1/n)-1)) = A078607(n).

%p a:= proc(n) option remember; `if`(n=0, 1, (s->

%p s^n-add(x^n, x=1..s-1))(ceil(1/(2^(1/n)-1))))

%p end:

%p seq(a(n), n=0..20); # _Alois P. Heinz_, May 09 2020

%t a[0] = 1; a[n_] := (s = Ceiling[1/(2^(1/n) - 1)])^n - Sum[k^n, {k, 1, s - 1}]; Array[a, 20, 0] (* _Amiram Eldar_, May 09 2020 *)

%o (PARI) {apply( A332097(n,s=1\(sqrtn(2,n-!n)-1))=(s+1)^n-sum(k=1,s,k^n)}, [0..20])

%Y Cf. A030052 (least k such that k^n = sum of distinct n-th powers).

%Y Cf. A078607 (s for which E(s) = a(n) <=> least k such that 2*k^n > (k+1)^n).

%Y Cf. A332065 (all k such that k^n is a sum of distinct n-th powers).

%Y Cf. A332101 (least k such that k^n <= sum of all smaller n-th powers).

%K nonn

%O 0,3

%A _M. F. Hasler_, May 07 2020

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Last modified April 24 05:49 EDT 2024. Contains 371918 sequences. (Running on oeis4.)