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A328654 Consider an empty list L, and for k = 1, 2, ...: if L contains a pair of consecutive terms summing to k, then let (u, v) be the first such pair: replace the two terms u and v in L with a single term k and set a(u) = v and a(v) = u, otherwise append k to L. 3

%I #12 Feb 27 2020 23:17:54

%S 2,1,4,3,6,5,11,9,8,12,7,10,14,13,16,15,18,17,20,19,23,27,21,44,26,25,

%T 22,29,28,32,39,30,34,33,49,37,36,40,31,38,42,41,45,24,43,47,46,50,35,

%U 48,57,53,52,55,54,58,51,56,60,59,63,67,61,124,66,65,62

%N Consider an empty list L, and for k = 1, 2, ...: if L contains a pair of consecutive terms summing to k, then let (u, v) be the first such pair: replace the two terms u and v in L with a single term k and set a(u) = v and a(v) = u, otherwise append k to L.

%C For any n > 0, a(n) is the value of the sibling of the node with value n in the binary tree described in A326936.

%C This sequence is a self-inverse permutation of the positive integers.

%H Rémy Sigrist, <a href="/A328654/b328654.txt">Table of n, a(n) for n = 1..10000</a>

%H Rémy Sigrist, <a href="/A328654/a328654.txt">C++ program for A328654</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%F A326936(n) + A326936(a(n)) = 0.

%e For n = 1:

%e - we set L = (1).

%e For n = 2:

%e - we set L = (1, 2).

%e For k = 3:

%e - the first two terms, (1, 2), sum to 3,

%e - so a(1) = 2 and a(2) = 1,

%e - we set L = (3).

%o (C++) See Links section.

%Y Cf. A326936.

%K nonn

%O 1,1

%A _Rémy Sigrist_, Oct 24 2019

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