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A327192 For any n >= 0: consider the different ways to split the binary representation of n into two (possibly empty) parts, say with value x and y; a(n) is the least possible value of max(x, y). 3

%I #12 Aug 26 2019 15:53:39

%S 0,1,1,1,1,1,2,3,1,1,2,3,3,3,3,3,1,1,2,3,4,5,5,5,3,3,3,3,4,5,6,7,1,1,

%T 2,3,4,5,6,7,5,5,5,5,5,5,6,7,3,3,3,3,4,5,6,7,7,7,7,7,7,7,7,7,1,1,2,3,

%U 4,5,6,7,8,9,9,9,9,9,9,9,5,5,5,5,5,5,6

%N For any n >= 0: consider the different ways to split the binary representation of n into two (possibly empty) parts, say with value x and y; a(n) is the least possible value of max(x, y).

%H Rémy Sigrist, <a href="/A327192/b327192.txt">Table of n, a(n) for n = 0..8192</a>

%F a(n) = 1 iff n = 2^k or n = 2^k + 1 for some k >= 0.

%e For n=42:

%e - the binary representation of 42 is "101010",

%e - there are 7 ways to split it:

%e - "" and "101010": x=0 and y=42: max(0, 42) = 42,

%e - "1" and "01010": x=1 and y=10: max(1, 10) = 10,

%e - "10" and "1010": x=2 and y=10: max(2, 10) = 10,

%e - "101" and "010": x=5 and y=2: max(5, 2) = 5,

%e - "1010" and "10": x=10 and y=2: max(10, 2) = 10,

%e - "10101" and "0": x=21 and y=0: max(21, 0) = 21,

%e - "101010" and "": x=42 and y=0: max(42, 0) = 42,

%e - hence a(42) = 5.

%o (PARI) a(n) = my (v=oo, b=binary(n)); for (w=0, #b, v=min(v, max(fromdigits(b[1..w],2), fromdigits(b[w+1..#b],2)))); v

%Y See A327186 for other variants.

%K nonn,look,base

%O 0,7

%A _Rémy Sigrist_, Aug 25 2019

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