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Sum of the sixth largest parts of the partitions of n into 9 parts.
9

%I #5 Jul 10 2019 07:38:13

%S 0,0,0,0,0,0,0,0,0,1,1,2,3,5,7,12,17,26,37,52,71,100,133,181,239,317,

%T 410,536,682,874,1104,1392,1735,2167,2670,3292,4025,4911,5947,7199,

%U 8645,10375,12377,14736,17456,20654,24307,28569,33441,39071,45478,52862

%N Sum of the sixth largest parts of the partitions of n into 9 parts.

%H <a href="/index/Par#part">Index entries for sequences related to partitions</a>

%F a(n) = Sum_{q=1..floor(n/9)} Sum_{p=q..floor((n-q)/8)} Sum_{o=p..floor((n-p-q)/7)} Sum_{m=o..floor((n-o-p-q)/6)} Sum_{l=m..floor((n-m-o-p-q)/5)} Sum_{k=l..floor((n-l-m-o-p-q)/4)} Sum_{j=k..floor((n-k-l-m-o-p-q)/3)} Sum_{i=j..floor((n-j-k-l-m-o-p-q)/2)} m.

%F a(n) = A326464(n) - A326465(n) - A326466(n) - A326467(n) - A326469(n) - A326470(n) - A326471(n) - A326472(n) - A326473(n).

%t Table[Sum[Sum[Sum[Sum[Sum[Sum[Sum[Sum[m, {i, j, Floor[(n - j - k - l - m - o - p - q)/2]}], {j, k, Floor[(n - k - l - m - o - p - q)/3]}], {k, l, Floor[(n - l - m - o - p - q)/4]}], {l, m, Floor[(n - m - o - p - q)/5]}], {m, o, Floor[(n - o - p - q)/6]}], {o, p, Floor[(n - p - q)/7]}], {p, q, Floor[(n - q)/8]}], {q, Floor[n/9]}], {n, 0, 50}]

%Y Cf. A026815, A326464, A326465, A326466, A326467, A326469, A326470, A326471, A326472, A326473.

%K nonn

%O 0,12

%A _Wesley Ivan Hurt_, Jul 10 2019