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%I #8 May 11 2019 02:24:05
%S 135,279,525,567,651,1143,1323,2079,2205,2295,2667,2835,3087,4123,
%T 4165,4185,4191,4445,4599,5355,5715,6223,8211,8255,8370,8415,8505,
%U 8925,9207,9359,9765,10731,11475,11811,12397,12495,13335,16575,16863,17010,17325,17577,17885,18423,18767,19467,21483,22995,23715,24583,24941,25039
%N Numbers n for which A325565(n) < A325568(n).
%H Antti Karttunen, <a href="/A325569/b325569.txt">Table of n, a(n) for n = 1..1001</a>
%e 135 has eight divisors: 1, 3, 5, 9, 15, 27, 45, 135. Of these only two, d = 1 and d = 9 are such that A048720(A065621(d),135/d) = 135, thus A325565(135) = 2. On the other hand, when iterating A325567 starting from 135 we get: A325567(135) = 9, A325567(9) = 3 and A325567(3) = 1, so A325568(135) = 3 > A325565(135), thus 135 is included in this sequence.
%o (PARI) isA325569(n) = (A325565(n)<A325568(n));
%Y Cf. A325565, A325567, A325568.
%K nonn
%O 1,1
%A _Antti Karttunen_, May 09 2019
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