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A323781 Numbers m such that Sum_{d|m} (tau(d)/sigma(d)) is an integer h where tau(k) = the number of the divisors of k (A000005) and sigma(k) = the sum of the divisors of k (A000203). 3

%I #15 Sep 08 2022 08:46:23

%S 1,15,429,609,6003,9156,20943,75579,90252,93849,115773,331359,631764,

%T 744993,817191,837655,925083,1130766,1141191,2349087,2491740,2512965,

%U 3040728,3266253,3796143,4314891,4365231,5025930,5294340,6135624,6629271,7210671,10906175

%N Numbers m such that Sum_{d|m} (tau(d)/sigma(d)) is an integer h where tau(k) = the number of the divisors of k (A000005) and sigma(k) = the sum of the divisors of k (A000203).

%C Sum_{d|n} (tau(d)/sigma(d)) > 1 for all n > 2.

%C Corresponding values of integers h: 1, 2, 2, 2, 2, 4, 2, 2, 4, 2, 2, 2, 5, 2, 2, 2, 2, 4, 2, 2, 5, 3, 4, 2, 2, 2, 2, 5, 5, 5, 2, 2, 2, ...

%C The smallest number m such that Sum_{d|m} (tau(d)/sigma(d)) is an integer h for h >= 1: 1, 15, 2512965, 9156, 631764, ...

%F A323780(a(n)) = 1.

%e 15 is a term because Sum_{d|15} (tau(d)/sigma(d)) = tau(1)/sigma(1) + tau(3)/sigma(3) + tau(5)/sigma(5) + tau(15)/sigma(15) = 1/1 + 2/4 + 2/6 + 4/24 = 2 (integer).

%t Select[Range[10^5], IntegerQ@ DivisorSum[#, Divide @@ DivisorSigma[{0, 1}, #] &] &] (* _Michael De Vlieger_, Feb 17 2019 *)

%o (Magma) [n: n in [1..1000000] | Denominator(&+[NumberOfDivisors(d) / SumOfDivisors(d): d in Divisors(n)]) eq 1]

%o (PARI) isok(n) = !frac(sumdiv(n, d, numdiv(d)/sigma(d))); \\ _Michel Marcus_, Feb 16 2019

%Y Cf. A000005, A000203, A323779, A323780.

%K nonn

%O 1,2

%A _Jaroslav Krizek_, Feb 16 2019

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Last modified April 25 05:18 EDT 2024. Contains 371964 sequences. (Running on oeis4.)