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%I #12 Aug 30 2019 02:44:43
%S 1,1,1,0,1,0,0,1,1,0,1,1,0,1,0,1,1,1,1,1,1,0,1,0,0,0,0,0,1,1,1,0,1,0,
%T 1,1,1,1,1,1,1,0,1,0,1,0,1,1,1,0,0,1,0,1,0,1,1,1,0,0,0,0,0,0,0,0,0,1,
%U 0,0,0,1,0,1,1,1,0,0,1,0,1,0,0,0,0,0,1,1
%N Digits of the 2-adic integer 7^(1/3).
%H Wikipedia, <a href="https://en.wikipedia.org/wiki/P-adic_number">p-adic number</a>
%F a(n) = (A322934(n+1) - A322934(n))/2^n.
%F a(n) = 0 if A322934(n)^3 - 7 is divisible by 2^(n+1), otherwise a(n) = 1.
%e Equals ...1111110101110000010111111010110110010111.
%o (PARI) a(n) = lift(sqrtn(7+O(2^(n+1)), 3))\2^n
%Y Cf. A322934.
%Y Digits of p-adic cubic roots:
%Y A323000 (2-adic, 3^(1/3));
%Y A323045 (2-adic, 5^(1/3));
%Y this sequence (2-adic, 7^(1/3));
%Y A323096 (2-adic, 9^(1/3));
%Y A290566 (5-adic, 2^(1/3));
%Y A290563 (5-adic, 3^(1/3));
%Y A309443 (5-adic, 4^(1/3));
%Y A319297, A319305, A319555 (7-adic, 6^(1/3));
%Y A321106, A321107, A321108 (13-adic, 5^(1/3)).
%K nonn,base
%O 0
%A _Jianing Song_, Aug 30 2019