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A321796 Prime p such that the prime before p is a substring of p^3. 0

%I #11 Jan 20 2022 15:59:48

%S 3,17,31,59,997,2837,57349,83773,224813,861743,9999991,61879669,

%T 95895673,763137931,1463016067,1608398527,6909512173,38095693807,

%U 94041857089,4913845865567

%N Prime p such that the prime before p is a substring of p^3.

%C 10^18-11 and 10^31-27 are also terms. - _Giovanni Resta_, Nov 20 2018

%e Prime before 3 is 2 and it is a substring of 3^3 = 27.

%p P:=proc(q) local a,n; for n from 2 to q do a:=ithprime(n);

%p if searchtext(convert(prevprime(a),string),convert(a^3,string))>0

%p then print(a); fi; od; end: P(10^5);

%t sub[x_, y_] := StringPosition @@ ToString /@ {x, y} != {}; p = Prime@ Range@ 100000; p[[Select[Range[2, 100000], sub[p[[#]]^3, p[[# - 1]]] &]]] (* _Giovanni Resta_, Nov 20 2018 *)

%t Select[Prime[Range[700000]],SequenceCount[IntegerDigits[#^3],IntegerDigits[ NextPrime[ #,-1]]]>0&] (* The program generates the first 11 terms of the sequence; to generate all terms, increase the Range constant to 174344399360 but the program will take an extremely long time to run. *) (* _Harvey P. Dale_, Mar 27 2020 *)

%o (Python)

%o from itertools import count, islice

%o from sympy import prevprime, prime

%o def A321796_gen(): return filter(lambda p: str(prevprime(p)) in str(p**3), (prime(n) for n in count(2)))

%o A321796_list = list(islice(A321796_gen(),5)) # _Chai Wah Wu_, Jan 20 2022

%Y Cf. A052075.

%K nonn,base,more

%O 1,1

%A _Paolo P. Lava_, Nov 19 2018

%E a(10)-a(20) from _Giovanni Resta_, Nov 20 2018

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Last modified April 25 03:15 EDT 2024. Contains 371964 sequences. (Running on oeis4.)