%I #19 Sep 05 2018 12:53:56
%S 1795234680,6807394251,7024396518,8597162403,9845617302,8201679453,
%T 2638150497,8037924561,7580612439,3179240586,8143950672,6927435018,
%U 4027596183,5987462031,2798305641,2791580364,2034871596,9135284607,5076213984,4860931572,8709235416,3947286510,7824315960,7362018594
%N The pandigital numbers that are divisible by the primes in A318787.
%C Pandigital version 1 (A050278) is used.
%C The last term is a(834218) = 9876541023, a multiple of 1097393447. - _Giovanni Resta_, Sep 04 2018
%H Jud McCranie, <a href="/A318788/b318788.txt">Table of n, a(n) for n = 1..1000</a>
%H Carlos Rivera, <a href="http://www.primepuzzles.net/puzzles/puzz_926.htm">Puzzle 926. pandigital and prime numbers</a>, The Prime Puzzles and Problems Connection.
%e 293339 is prime and 1795234680 is the only pandigitial number that it divides, so 1795234680 is in the sequence.
%Y Cf. A050278, A318787.
%K nonn,base,fini
%O 1,1
%A _Jud McCranie_, Sep 03 2018