%I #33 Sep 04 2018 15:45:23
%S 4,3,6,2,5,9,4,8,9,0,8,5,4,7,3,4,2,7,3,0,5,0,9,4,2,3,6,2,5,9,1,0,9,2,
%T 9,5,1,8,2,2,9,4,9,5,9,5,3,2,3,5,5,9,3,2,0,3,8,4,9,0,5,5,4,7,7,5,2,7,
%U 8,0,3,8,3,3,6,7,1,5,4,5,3,7,4,1,7,0,4,1,9,5,9,4,6,4,8,0,2
%N The 10-adic integer a = ...580984952634 satisfying a^3 + 1 = b, b^3 + 1 = c, c^3 + 1 = d, and d^3 + 1 = a.
%C There is one other automorphic cube-ring of four 10-adic integers.
%H Seiichi Manyama, <a href="/A317698/b317698.txt">Table of n, a(n) for n = 0..1000</a>
%e 634^3 + 1 == 105 (mod 10^3), 105^3 + 1 == 626 (mod 10^3), 626^3 + 1 == 377 (mod 10^3), and 377^3 + 1 == 634 (mod 10^3), so the sequence begins 4 3 6.
%Y Cf. A318299 (b), A318300 (c), A318302 (d).
%Y Cf. A318135, A318136, A318137, A318138, A318139, A318140.
%K nonn,base
%O 0,1
%A _Patrick A. Thomas_, Aug 20 2018
%E More terms from _Seiichi Manyama_, Aug 24 2018
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