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%I #14 Aug 27 2019 17:59:07
%S 0,1,3,3,5,6,8,9,7,10,11,13,12,14,15,16,17,16,21,20,21,15,21,23,20,25,
%T 27,24,24,28,28,23,32,36,29,33,33,33,35,27,37,36,38,38,43,33,43,42,43,
%U 40,29,48,43,31,51,44,53,38,52,47,57,47,35,57,48,48,66,55,57
%N a(n) = A309891(A025487(n)): For each prime signature, gives the sum of the number of trailing zeros for all bases b >= 2 for some number m with that prime signature. The prime signatures are chosen in order in which they are first seen in the positive integers.
%C A309891(n) only depends on the prime signature of n. This sequence lists the values for different prime signatures based on A025487 which lists the least positive integer for each prime signature.
%e A309891(A025487(6)) = A309891(12) = 6.
%Y Cf. A025487, A309891.
%K nonn,easy
%O 1,3
%A _David A. Corneth_, Aug 24 2019
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