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%I #13 May 25 2019 11:49:30
%S 2487159630,2581740963,3697512840,3751908642,3791508642,3796512840,
%T 4283716590,4573921680,4609785321,4832716590,4960785321,4976853210,
%U 5016793284,5071693284,5106793284,5170693284,5179386420,5187429630,5389710642,5397186420,5473921680,5710693284,5731908642,5786413290,5791308642,5809764321,5839710642,5847102963,5897130642,5897643210,5907864321
%N "Autotomy numbers" that have exactly 10 distinct decimal digits. Subtracting their last digit from the remaining part produces a shorter autotomy number (still with no duplicate digit). This process is iterated until the remaining part has only one digit (details in the Example section).
%C The sequence is finite and has 182 terms; a(182) = 9876543210.
%H Jean-Marc Falcoz, <a href="/A308377/b308377.txt">Table of n, a(n) for n = 1..182</a>
%H Eric Angelini, <a href="https://cinquantesignes.blogspot.com/2019/05/pandigitaux-et-saucissons.html">Pandigitaux et saucissons</a> (in French).
%e a(2) = 2581740963
%e Subtract 3 (last digit) from the remaining part 258174096 = 258174093
%e Subtract 3 (last digit) from the remaining part 25817409 = 25817406
%e Subtract 6 (last digit) from the remaining part 2581740 = 2581734
%e Subtract 4 (last digit) from the remaining part 258173 = 258169
%e Subtract 9 (last digit) from the remaining part 25816 = 25807
%e Subtract 7 (last digit) from the remaining part 2580 = 2573
%e Subtract 3 (last digit) from the remaining part 257 = 254
%e Subtract 4 (last digit) from the remaining part 25 = 21
%e Subtract 1 (last digit) from the remaining part 2 = 1 (single digit, end).
%Y Cf. A308393 (definition of an "autotomy number", A050278 (pandigital numbers, version 1: each digit appears exactly once), A171102 (pandigital numbers, version 2: each digit appears at least once).
%K base,nonn,fini
%O 1,1
%A _Eric Angelini_ and _Jean-Marc Falcoz_, May 23 2019
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