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%I #25 Dec 06 2019 21:44:52
%S 1,2,3,4,5,6,7,8,9,10,12,13,15,16,18,19,21,22,24,25,30,31,36,40,45,46,
%T 70,85,91,105,106,120
%N Numbers k such that every prime p <= sqrt(k) divides k*(k-1).
%C If k is in the sequence, the first Chebyshev function theta(sqrt(k)) = Sum_{p <= sqrt(k)} log(p) <= 2 log(k). Now it is known that theta(x) = x + O(x/log(x)), so this can't happen if k is sufficiently large. Thus the sequence is finite.
%C For x >= 2, theta(x) >= x - 1.2323*x/log(x) (see Dusart, Theorem 5.2). Thus theta(sqrt(k)) > 2*log(k) for k >= 417. Since there are no other terms < 417, the largest term is 120.
%H P. Dusart, <a href="https://arxiv.org/abs/1002.0442">Estimates of Some Functions Over Primes without R.H.</a>, arXiv:1002.0442 [math.NT], 2010.
%e 120 is in the sequence because all primes <= sqrt(120) (namely 2,3,5,7) divide 120*119.
%p Res:= NULL:
%p P:= 1:
%p q:= 2: t:= 4:
%p for n from 1 to 10^6 do
%p if n = t then P:= P*q; q:= nextprime(q); t:= q^2 fi;
%p if n*(n-1) mod P = 0 then Res:= Res, n fi
%p od:
%p Res;
%t seqQ[k_] := AllTrue[Select[Range@Floor@Sqrt@k, PrimeQ], Divisible[k (k - 1), #] &]; Select[Range[120], seqQ] (* _Amiram Eldar_, Apr 03 2019 *)
%o (Sage)
%o def isA307345(k):
%o r = prime_range(isqrt(k)+1)
%o return all([p.divides(k*(k-1)) for p in r])
%o print([n for n in (1..120) if isA307345(n)]) # _Peter Luschny_, Apr 03 2019
%o (PARI) isok(k) = forprime(p=1, sqrtint(k), if (k*(k-1) % p, return(0))); return(1); \\ _Michel Marcus_, Apr 05 2019
%Y Contains A323215.
%K nonn,fini,full
%O 1,2
%A _Robert Israel_, Apr 03 2019
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