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%I #14 Mar 26 2019 20:35:36
%S 33,242,7939375,76571890623,104228508212890623,1489106237081787109375,
%T 273062471666259918212890623,804505911103256259918212890623,
%U 490685203356467392256259918212890623,6794675247932944436619977392256259918212890623,329757106427071213106619977392256259918212890623
%N Smallest number m such that m, m+1, and m+2 all have exactly 2p divisors, where p = prime(n).
%C a(4) was incorrect in "Some new results on consecutive equidivisible integers".
%H Chai Wah Wu, <a href="/A306879/b306879.txt">Table of n, a(n) for n = 1..50</a>
%H Vasilii A. Dziubenko, Vladimir A. Letsko, <a href="https://arxiv.org/abs/1811.05127">Consecutive positive integers with the same number of divisors</a>, arXiv:1811.05127 [math.NT], 2018.
%H Vladimir A. Letsko, <a href="http://arxiv.org/abs/1510.07081">Some new results on consecutive equidivisible integers</a>, arXiv:1510.07081 [math.NT], 2015.
%e 33, 34, 35 all have exactly 2*prime(1) = 4 divisors, and 33 is the smallest number with this property, so a(1) = 33.
%Y Cf. A274639.
%Y A subsequence of A075040.
%K nonn
%O 1,1
%A _Chai Wah Wu_, Mar 14 2019
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