

A301810


Smallest prime that starts a sequence of at least n consecutive primes with a difference of 210.


0




OFFSET

1,1


COMMENTS

a(n) is the first prime of the sequence.
a(1) = 2. Thereafter, a(n) = smallest p such that p + 210*(k1) and p + 210*k are consecutive primes for all 1 <= k <= n  1.  Altug Alkan, Mar 27 2018


LINKS



EXAMPLE

a(2)=20831323 since the first prime gap of 210 starts at 20831323.


CROSSREFS



KEYWORD

nonn,hard,more


AUTHOR



EXTENSIONS



STATUS

approved



