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%I #5 Jan 25 2018 17:46:37
%S 1,1,2,3,4,5,146,4207,26329,257721,3556495,42685181,631230381,
%T 9409600499,142557084957,2781352245050,52598395446786,950288577530017,
%U 20768368026768594,448759012546543804,9652848877533217174,235179507693424886403,5756272592837812726164,140920987987840184113287
%N Number of ordered ways of writing n^3 as a sum of n nonnegative cubes.
%H <a href="/index/Su#ssq">Index entries for sequences related to sums of cubes</a>
%F a(n) = [x^(n^3)] (Sum_{k>=0} x^(k^3))^n.
%e a(3) = 3 because we have [27, 0, 0], [0, 27, 0] and [0, 0, 27].
%t Table[SeriesCoefficient[Sum[x^k^3, {k, 0, n}]^n, {x, 0, n^3}], {n, 0, 23}]
%Y Cf. A000578, A030272, A232173, A259792, A290054, A290247, A291700, A298329, A298330, A298641, A298672.
%K nonn
%O 0,3
%A _Ilya Gutkovskiy_, Jan 24 2018
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