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%I #14 Sep 06 2021 10:20:52
%S 1,4,9,12,25,36,40,52,80,92,124,150,208,306,361,630,656,1648,1780,
%T 2508,3300,3540,5728,6260,6450,7500,10820,12656,14076,14132,18836,
%U 20960,23456,24272,35280,43136
%N Numbers k such that 2^m == 2 (mod m*(m+1)), where m = A019320(k).
%C Also, numbers k such that A019320(k) belongs to A216822.
%o (PARI) is_A297414(k) = my(m=polcyclo(k, 2)); Mod(2, m*(m+1))^m==2;
%Y Cf. A019320, A216822, A297413, A297415.
%K nonn
%O 1,2
%A _Max Alekseyev_, Dec 29 2017
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