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%I #8 Jan 27 2023 19:27:54
%S 5,10,11,15,16,17,20,21,22,23,25,30,50,55,56,60,61,75,80,81,85,86,87,
%T 90,91,92,100,105,106,110,111,112,115,116,117,118,120,121,122,123,125,
%U 130,135,136,140,141,142,145,146,147,148,150,155,180,205,210,211
%N Numbers whose base-5 digits d(m), d(m-1), ... d(0) have #(rises) < #(falls); see Comments.
%C A rise is an index i such that d(i) < d(i+1); a fall is an index i such that d(i) > d(i+1). The sequences A296697-A296699 partition the natural numbers. See the guide at A296712.
%H Clark Kimberling, <a href="/A296699/b296699.txt">Table of n, a(n) for n = 1..10000</a>
%e The base-5 digits of 211 are 1,3,2,1; here #(rises) = 1 and #(falls) = 2, so 211 is in the sequence.
%t z = 200; b = 5; d[n_] := Sign[Differences[IntegerDigits[n, b]]];
%t Select[Range [z], Count[d[#], -1] == Count[d[#], 1] &] (* A296697 *)
%t Select[Range [z], Count[d[#], -1] < Count[d[#], 1] &] (* A296698 *)
%t Select[Range [z], Count[d[#], -1] > Count[d[#], 1] &] (* A296699 *)
%Y Cf. A296697, A296698, A296712.
%K nonn,base
%O 1,1
%A _Clark Kimberling_, Dec 21 2017
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