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A293820
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Number of integer-sided polygons having perimeter n, modulo rotations but not reflections.
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7
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1, 1, 3, 5, 11, 19, 43, 75, 155, 287, 567, 1053, 2063, 3859, 7455, 14089, 27083, 51463, 98855, 188697, 362675, 695155, 1338087, 2573235, 4962875, 9571195, 18496407, 35759799, 69240899, 134154259, 260235639, 505163055, 981575759, 1908619755, 3714304167, 7233118641, 14095779055
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OFFSET
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3,3
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COMMENTS
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Rotations are counted only once, but reflections are considered different. For a polygon to be nondegenerate, the longest side must be shorter than the sum of the remaining sides (equivalently, shorter than n/2). These are row sums of A293819.
A formula is given in Section 6 of the East and Niles article.
The same article shows that a(n) is asymptotic to 2^n / n.
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LINKS
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FORMULA
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a(n) = (Sum_{d|n} phi(n/d)*2^d)/n - 1 - 2^floor(n/2). - Andrew Howroyd, Nov 21 2017
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EXAMPLE
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There are 11 polygons having perimeter 7: 2 triangles (331, 322), 4 quadrilaterals (3211, 3121, 3112, 2221), 3 pentagons (31111, 22111, 21211), 1 hexagon (211111) and 1 heptagon (1111111).
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MATHEMATICA
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T[n_, k_] := DivisorSum[GCD[n, k], EulerPhi[#]*Binomial[n/#, k/#] &]/n - Binomial[Floor[n/2], k - 1];
a[n_] := Sum[T[n, k], {k, 3, n}]
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PROG
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(PARI) a(n) = sumdiv(n, d, eulerphi(n/d)*2^d)/n - 1 - 2^floor(n/2); \\ Andrew Howroyd, Nov 21 2017
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CROSSREFS
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Row sums of A293819 (k-gon triangle).
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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