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A293258
Decimal expansion of product of 1 - 4^-p over all primes p.
0
9, 2, 1, 8, 9, 3, 8, 3, 5, 2, 9, 6, 9, 3, 1, 8, 5, 9, 1, 9, 4, 6, 7, 0, 3, 0, 2, 7, 9, 9, 8, 0, 7, 1, 8, 6, 7, 3, 2, 2, 0, 5, 4, 7, 8, 7, 3, 8, 8, 6, 2, 6, 7, 4, 9, 7, 6, 2, 3, 0, 6, 6, 0, 3, 9, 3, 8, 6, 4, 4, 5, 3, 1, 2, 2, 8, 6, 0, 8, 9, 3, 7, 0, 9, 3, 8, 7, 5, 6, 0, 5, 5, 6, 0, 8, 5, 5, 3, 9, 4, 8, 7, 0, 2, 6
OFFSET
0,1
COMMENTS
Knopfmacher proves that prime(n+1) = floor(1 - log(1 - A/P)) where A is this constant and P is the product (1 - 4^-2)(1 - 4^-3)(1 - 4^-5)...(1 - 4^-prime(n)).
LINKS
John Knopfmacher, Recursive formulae for prime numbers, Archiv der Mathematik (Basel) 33:2 (1979/80), pp. 144-149.
FORMULA
Equals A184082 * A184083 = A184082 / A184084. - Amiram Eldar, Nov 16 2021
EXAMPLE
0.921893835296931859194670302799807186732205478738862674976230660393864453122...
PROG
(PARI) prodeuler(p=2, bitprecision(1.)/2+2, 1-4.^-p)
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
STATUS
approved